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Mathematics · JEE | DETERMINANTS
हिन्दीIf \( A \) is a square matrix satisfying \( A^2 - 4A + I = 0 \), then \( A^{-1} \) is given by:
View Answer & Solution
Correct answer · Option C
\( 4I - A \)
Explanation
Post-multiplying the equation by \( A^{-1} \) gives \( A - 4I + A^{-1} = 0 \implies A^{-1} = 4I - A \).
