Physics · JEE | OSCILLATIONS
हिन्दीIf a periodic function is expressed as \( f(t) = A\sin(\omega t) + B\cos(\omega t) \), it can be rewritten in the form \( f(t) = D\sin(\omega t + \phi) \). What is the value of amplitude \( D \)?
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Correct answer · Option D
\( \sqrt{A^2 + B^2} \)
Explanation
By taking \( A = D\cos\phi \) and \( B = D\sin\phi \), the resultant amplitude is \( D = \sqrt{A^2 + B^2} \).