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Physics · JEE | OSCILLATIONS

हिन्दी

If the displacement of a particle in SHM is given by \( x(t) = A\cos(\omega t + \phi) \), what is the expression for its instantaneous acceleration \( a(t) \)?

  1. A
    \( -\omega A \sin(\omega t + \phi) \)
  2. B
    \( -\omega^2 A \cos(\omega t + \phi) \)
  3. C
    \( \omega^2 A \cos(\omega t + \phi) \)
  4. D
    \( \omega A \cos(\omega t + \phi) \)
View Answer & Solution

Correct answer · Option B

\( -\omega^2 A \cos(\omega t + \phi) \)

Explanation

Differentiating displacement twice with respect to time gives \( a(t) = \frac{d^2 x}{dt^2} = -\omega^2 A\cos(\omega t + \phi) \).
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