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Mathematics · JEE | THREE DIMENSIONAL GEOMETRY

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यदि रेखाएँ \( \frac{1-x}{3} = \frac{7y-14}{2p} = \frac{z-3}{2} \) तथा \( \frac{7-7x}{3p} = \frac{y-5}{1} = \frac{6-z}{5} \) परस्पर लंबवत हैं, तो \( p \) का मान है:

  1. A
    \( \frac{10}{7} \)
  2. B
    \( \frac{70}{11} \)
  3. C
    \( \frac{11}{7} \)
  4. D
    \( \frac{7}{11} \)
उत्तर और समाधान देखें

सही उत्तर · विकल्प B

\( \frac{70}{11} \)

व्याख्या

Standard forms have direction ratios \( (-3, \frac{2p}{7}, 2) \) and \( (-\frac{3p}{7}, 1, -5) \). For perpendicularity, \( (-3)(-\frac{3p}{7}) + (\frac{2p}{7})(1) + (2)(-5) = 0 \implies \frac{9p}{7} + \frac{2p}{7} - 10 = 0 \implies \frac{11p}{7} = 10 \implies p = \frac{70}{11} \).
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