OnlineCBT
Mathematics · JEE | THREE DIMENSIONAL GEOMETRY
हिन्दीIf the lines \( \frac{x-1}{-3} = \frac{y-2}{2k} = \frac{z-3}{2} \) and \( \frac{x-1}{3k} = \frac{y-1}{1} = \frac{z-6}{-5} \) are perpendicular, then the value of \( k \) is:
View Answer & Solution
Correct answer · Option B
\( -\frac{10}{7} \)
Explanation
For perpendicular lines, \( a_1 a_2 + b_1 b_2 + c_1 c_2 = 0 \implies (-3)(3k) + (2k)(1) + (2)(-5) = 0 \implies -9k + 2k - 10 = 0 \implies -7k = 10 \implies k = -\frac{10}{7} \).
