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Physics · PYQ NEET UG 2016(1)
हिन्दीIf the velocity of a particle is \( v = At + Bt^2 \), where \( A \) and \( B \) are constants, then the distance travelled by it between \( 1\text{ s} \) and \( 2\text{ s} \) is
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Correct answer · Option B
\( \frac{3}{2}A + \frac{7}{3}B \)
Explanation
Distance \( S = \int_{1}^{2} (At + Bt^2) dt = [\frac{A}{2}t^2 + \frac{B}{3}t^3]_{1}^{2} = \frac{A}{2}(4-1) + \frac{B}{3}(8-1) = \frac{3}{2}A + \frac{7}{3}B \).
