OnlineCBT
Mathematics · JEE | DETERMINANTS
हिन्दीIf the vertices of a triangle are \( (2, -6), (5, 4) \) and \( (k, 4) \), and its area is \( 35 \text{ sq units} \), then the sum of all possible values of \( k \) is:
View Answer & Solution
Correct answer · Option A
\( 10 \)
Explanation
\( \Delta = \frac{1}{2} | 2(4-4) + 5(4 - (-6)) + k(-6-4) | = \frac{1}{2} | 50 - 10k | = | 25 - 5k | = 35 \implies 25 - 5k = \pm 35 \implies 5k = -10 \text{ or } 60 \implies k = -2, 12 \). Sum \( = -2 + 12 = 10 \).
