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Physics · PYQ NEET UG 2024

हिन्दी

If \( x = 5\sin(\pi t + \frac{\pi}{3})\text{ m} \) represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are :

  1. A
    5 cm, 1 s
  2. B
    5 m, 1 s
  3. C
    5 cm, 2 s
  4. D
    5 m, 2 s
View Answer & Solution

Correct answer · Option D

5 m, 2 s

Explanation

Comparing with standard SHM equation \( x = A\sin(\omega t + \phi) \): Amplitude \( A = 5\text{ m} \). Angular frequency \( \omega = \pi\text{ rad/s} \). Time period \( T = \frac{2\pi}{\omega} = \frac{2\pi}{\pi} = 2\text{ s} \).
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