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Mathematics · JEE | COMPLEX NUMBERS AND QUADRATIC EQUATIONS
Englishयदि \( x + iy = \frac{a + ib}{a - ib} \) है, तो \( x^2 + y^2 \) का मान है:
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सही उत्तर · विकल्प C
\( 1 \)
व्याख्या
Taking modulus on both sides, \( |x + iy| = \left|\frac{a + ib}{a - ib}\right| \). Since \( |a + ib| = |a - ib| = \sqrt{a^2 + b^2} \), we get \( \sqrt{x^2 + y^2} = 1 \implies x^2 + y^2 = 1 \).
