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Physics · JEE | WORK, ENERGY AND POWER

हिन्दी

In a completely inelastic head-on collision between two masses \( m_1 \) (moving with speed \( v_{1i} \)) and \( m_2 \) (at rest), the final common velocity \( v_f \) of the combined masses is given by:

  1. A
    \( v_f = \frac{m_2 v_{1i}}{m_1 + m_2} \)
  2. B
    \( v_f = \frac{m_1 v_{1i}}{m_1 + m_2} \)
  3. C
    \( v_f = \frac{(m_1 + m_2)v_{1i}}{m_1} \)
  4. D
    \( v_f = \frac{m_1 - m_2}{m_1 + m_2} v_{1i} \)
View Answer & Solution

Correct answer · Option B

\( v_f = \frac{m_1 v_{1i}}{m_1 + m_2} \)

Explanation

Using conservation of linear momentum: \( m_1 v_{1i} = (m_1 + m_2)v_f \), which gives \( v_f = \frac{m_1 v_{1i}}{m_1 + m_2} \).
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