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Physics · JEE | MECHANICAL PROPERTIES OF FLUIDS

हिन्दी

In a hydraulic lift, two pistons of cross-sectional areas \( A_1 \) and \( A_2 \) are used. If a force \( F_1 \) is applied on the smaller piston, the upward force \( F_2 \) on the larger piston is given by:

  1. A
    \( F_2 = F_1 (\frac{A_1}{A_2}) \)
  2. B
    \( F_2 = F_1 + \frac{A_2}{A_1} \)
  3. C
    \( F_2 = F_1 (\frac{A_1}{A_2})^2 \)
  4. D
    \( F_2 = F_1 (\frac{A_2}{A_1}) \)
View Answer & Solution

Correct answer · Option D

\( F_2 = F_1 (\frac{A_2}{A_1}) \)

Explanation

By Pascal's law, pressure \( P = \frac{F_1}{A_1} = \frac{F_2}{A_2} \), which gives \( F_2 = F_1 (\frac{A_2}{A_1}) \).
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