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Physics · UNITS AND MEASUREMENT

हिन्दी

In a system of units where Force \( (F) \), Velocity \( (v) \), and Time \( (t) \) are chosen as fundamental quantities, the dimensional formula of mass \( (m) \) is:

  1. A
    \( [F v^{-1} t] \)
  2. B
    \( [F v t^{-1}] \)
  3. C
    \( [F v^{-1} t^{-1}] \)
  4. D
    \( [F v t] \)
View Answer & Solution

Correct answer · Option A

\( [F v^{-1} t] \)

Explanation

Let \( m = F^a v^b t^c \). In terms of base dimensions: \( [M] = [M L T^{-2}]^a [L T^{-1}]^b [T]^c \). Comparing exponents gives \( a = 1 \), \( a + b = 0 \implies b = -1 \), and \( -2a - b + c = 0 \implies c = 1 \). Hence \( [m] = [F v^{-1} t] \).
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