Physics · JEE | WORK, ENERGY AND POWER
हिन्दीIn a two-dimensional elastic collision between two masses \( m_1 \) and \( m_2 \) with initial velocity \( v_{1i} \) along the x-axis, what is the equation representing the conservation of momentum along the y-axis (where \( \theta_1 \) and \( \theta_2 \) are the scattering angles)?
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Correct answer · Option C
\( 0 = m_1 v_{1f} \sin\theta_1 - m_2 v_{2f} \sin\theta_2 \)
Explanation
Initial momentum along y-axis is zero. Equating sum of y-components of final momenta to zero gives \( 0 = m_1 v_{1f} \sin\theta_1 - m_2 v_{2f} \sin\theta_2 \).