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Physics · JEE | WORK, ENERGY AND POWER

हिन्दी

In a two-dimensional elastic collision between two masses \( m_1 \) and \( m_2 \) with initial velocity \( v_{1i} \) along the x-axis, what is the equation representing the conservation of momentum along the y-axis (where \( \theta_1 \) and \( \theta_2 \) are the scattering angles)?

  1. A
    \( m_1 v_{1i} = m_1 v_{1f} \cos\theta_1 + m_2 v_{2f} \cos\theta_2 \)
  2. B
    \( m_1 v_{1i} \sin\theta_1 = m_2 v_{2f} \sin\theta_2 \)
  3. C
    \( 0 = m_1 v_{1f} \sin\theta_1 - m_2 v_{2f} \sin\theta_2 \)
  4. D
    \( m_1 v_{1f} \sin\theta_1 + m_2 v_{2f} \sin\theta_2 = m_1 v_{1i} \)
View Answer & Solution

Correct answer · Option C

\( 0 = m_1 v_{1f} \sin\theta_1 - m_2 v_{2f} \sin\theta_2 \)

Explanation

Initial momentum along y-axis is zero. Equating sum of y-components of final momenta to zero gives \( 0 = m_1 v_{1f} \sin\theta_1 - m_2 v_{2f} \sin\theta_2 \).
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