Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीIn an ethene molecule (\( \text{C}_2\text{H}_4 \)), the reported \( \text{H}-\text{C}-\text{H} \) angle is \( 117.6^\circ \). Assuming planar symmetry such that the two \( \text{H}-\text{C}-\text{C} \) angles are identical, calculate each \( \text{H}-\text{C}-\text{C} \) bond angle.
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Correct answer · Option A
\( 121.2^\circ \)
Explanation
Around each carbon, total angle sum = 360°. Thus, 2 × (H–C–C) + 117.6° = 360° ⇒ 2 × (H–C–C) = 242.4° ⇒ H–C–C = 121.2° (textbook rounds to ~121°).