OnlineCBT Logo OnlineCBT

Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

In an ethene molecule (\( \text{C}_2\text{H}_4 \)), the reported \( \text{H}-\text{C}-\text{H} \) angle is \( 117.6^\circ \). Assuming planar symmetry such that the two \( \text{H}-\text{C}-\text{C} \) angles are identical, calculate each \( \text{H}-\text{C}-\text{C} \) bond angle.

  1. A
    \( 121.2^\circ \)
  2. B
    \( 120.0^\circ \)
  3. C
    \( 122.4^\circ \)
  4. D
    \( 118.8^\circ \)
View Answer & Solution

Correct answer · Option A

\( 121.2^\circ \)

Explanation

Around each carbon, total angle sum = 360°. Thus, 2 × (H–C–C) + 117.6° = 360° ⇒ 2 × (H–C–C) = 242.4° ⇒ H–C–C = 121.2° (textbook rounds to ~121°).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat