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Chemistry · Organic chemistry – some basic principles and techniques

हिन्दी

In Carius method for the estimation of bromine, 0.25 g of an organic compound yielded 0.376 g of silver bromide. The percentage of bromine present in the compound is: (Molar mass of \( \text{AgBr} = 188\text{ g mol}^{-1} \), Atomic mass of \( \text{Br} = 80\text{ u} \))

  1. A
    32.0%
  2. B
    48.0%
  3. C
    64.0%
  4. D
    80.0%
View Answer & Solution

Correct answer · Option C

64.0%

Explanation

\( \%\text{Br} = \frac{80 \times 0.376 \times 100}{188 \times 0.25} = \frac{30.08}{0.47} = 64.0\% \).
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