Chemistry · Organic chemistry – some basic principles and techniques
हिन्दीIn Carius method for the estimation of bromine, 0.25 g of an organic compound yielded 0.376 g of silver bromide. The percentage of bromine present in the compound is: (Molar mass of \( \text{AgBr} = 188\text{ g mol}^{-1} \), Atomic mass of \( \text{Br} = 80\text{ u} \))
View Answer & Solution
Correct answer · Option C
64.0%
Explanation
\( \%\text{Br} = \frac{80 \times 0.376 \times 100}{188 \times 0.25} = \frac{30.08}{0.47} = 64.0\% \).