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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

In \( \text{NH}_3 \) and \( \text{NF}_3 \), both have pyramidal geometry with nitrogen having a lone pair. Given that \( \mu_{\text{NH}_3} = 4.90 \times 10^{-30}\text{ C m} \) and \( \mu_{\text{NF}_3} = 0.80 \times 10^{-30}\text{ C m} \), calculate the numerical ratio \( \mu_{\text{NH}_3} / \mu_{\text{NF}_3} \) expressed to two decimal places.

  1. A
    \( 3.85 \)
  2. B
    \( 5.24 \)
  3. C
    \( 6.13 \)
  4. D
    \( 7.42 \)
View Answer & Solution

Correct answer · Option C

\( 6.13 \)

Explanation

\( \frac{\mu_{\text{NH}_3}}{\mu_{\text{NF}_3}} = \frac{4.90 \times 10^{-30}}{0.80 \times 10^{-30}} = \frac{4.90}{0.80} = 6.125 \approx 6.13 \).
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