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Chemistry · JEE | Haloalkanes and Haloarenes

हिन्दी

In the comparison of \( \text{S}_N1 \) reactivity among isomeric bromobutanes (\( \text{C}_4\text{H}_9\text{Br} \)), which compound exhibits the highest reactivity?

  1. A
    \( \text{tert-Butyl bromide } [(\text{CH}_3)_3\text{CBr}] \)
  2. B
    \( \text{1-Bromobutane } (\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{Br}) \)
  3. C
    \( \text{2-Bromobutane } (\text{CH}_3\text{CH}_2\text{CH(Br)CH}_3) \)
  4. D
    \( \text{Isobutyl bromide } [(\text{CH}_3)_2\text{CHCH}_2\text{Br}] \)
View Answer & Solution

Correct answer · Option A

\( \text{tert-Butyl bromide } [(\text{CH}_3)_3\text{CBr}] \)

Explanation

Tertiary butyl bromide forms a highly stable tertiary carbocation, making it the most reactive among isomeric bromobutanes in \( \text{S}_N1 \) reactions.
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