Physics · JEE | MOTION IN A PLANE
हिन्दीIn three dimensions, if a vector \( \mathbf{A} \) makes angles \( \alpha \), \( \beta \), and \( \gamma \) with the \( x\text{-} \), \( y\text{-} \), and \( z\text{-axes} \) respectively, the magnitude of \( \mathbf{A} \) is given by:
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Correct answer · Option D
\( A = \sqrt{A_x^2 + A_y^2 + A_z^2} \)
Explanation
In 3D rectangular coordinates, magnitude of vector \( \mathbf{A} \) is \( \sqrt{A_x^2 + A_y^2 + A_z^2} \), where \( A_x = A\cos\alpha \), etc.