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Mathematics · JEE I SETS
हिन्दीLet \( A = \{ x \in \mathbb{R} : x^2 - 16 = 0 \} \) and \( B = \{ x \in \mathbb{R} : x^2 - 2 = 0 \} \). If \( S = \{ x \in \mathbb{Q} : x \in A \cup B \} \), then the number of subsets of \( S \) is:
View Answer & Solution
Correct answer · Option B
4
Explanation
\( A = \{-4, 4\} \) and \( B = \{-\sqrt{2}, \sqrt{2}\} \). The rational elements in \( A \cup B \) are \( \{-4, 4\} \), so \( n(S) = 2 \). The number of subsets is \( 2^2 = 4 \).
