OnlineCBT
Mathematics · JEE I SETS
हिन्दीLet \( A = \{x \in \mathbb{R} : x^2 - 8x + 12 = 0\} \), \( B = \{2, 4, 6\} \), and \( D = \{6\} \). If \( S = \{X \subset B : D \subset X \text{ and } X \not\subset A\} \), then the number of sets in \( S \) is:
View Answer & Solution
Correct answer · Option B
\( 2 \)
Explanation
\( A = \{2, 6\} \). Subsets \( X \subset B \) with \( 6 \in X \) are \( \{6\}, \{2, 6\}, \{4, 6\}, \{2, 4, 6\} \). Among these, \( \{6\} \subset A \) and \( \{2, 6\} \subset A \). The remaining sets are \( \{4, 6\} \) and \( \{2, 4, 6\} \), so there are \( 2 \) such sets.
