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Mathematics · JEE | PROBABILITY

हिन्दी

Let \( E \) and \( F \) be two events such that \( P(E) = \frac{1}{4} \), \( P(F) = \frac{1}{2} \), and \( P(E \cap F) = \frac{1}{8} \). The value of \( P(E \mid F) \) is:

  1. A
    \( \frac{1}{2} \)
  2. B
    \( \frac{1}{4} \)
  3. C
    \( \frac{3}{8} \)
  4. D
    \( \frac{1}{8} \)
View Answer & Solution

Correct answer · Option A

\( \frac{1}{2} \)

Explanation

Using conditional probability, \( P(E \mid F) = \frac{P(E \cap F)}{P(F)} = \frac{1/8}{1/2} = \frac{1}{4} \).
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