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Chemistry · PYQ NEET UG 2024
हिन्दीMass in grams of copper deposited by passing \( 9.6487 \text{ A} \) current through a voltmeter containing copper sulphate solution for \( 100 \text{ seconds} \) is: (Given: Molar mass of \( \text{Cu} : 63 \text{ g mol}^{-1} \), \( 1\text{F} = 96487 \text{ C} \))
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Correct answer · Option D
0.315 g
Explanation
Using Faraday's law, \( W = \frac{E \cdot I \cdot t}{F} = \frac{(63/2) \cdot 9.6487 \cdot 100}{96487} = 0.315 \text{ g} \).
