OnlineCBT Logo OnlineCBT

Chemistry · THERMODYNAMICS

हिन्दी

Match List-I with List-II based on mean bond enthalpies at 298 K: List-I (Bond Type) List-II (Mean Bond Enthalpy in kJ mol-1) A \( \text{C}-\text{C} \) I \( 837 \) B \( \text{C}=\text{C} \) II \( 347 \) C \( \text{C}\equiv\text{C} \) III \( 1070 \) D \( \text{C}\equiv\text{O} \) IV \( 611 \) Choose the correct answer from the options given below:

Match List-I with List-II based on mean bond enthalpies at 298 K:

List-I (Bond Type) List-II (Mean Bond Enthalpy in kJ mol-1)
A \( \text{C}-\text{C} \) I \( 837 \)
B \( \text{C}=\text{C} \) II \( 347 \)
C \( \text{C}\equiv\text{C} \) III \( 1070 \)
D \( \text{C}\equiv\text{O} \) IV \( 611 \)

Choose the correct answer from the options given below:

  1. A
    A-(I), B-(IV), C-(II), D-(III)
  2. B
    A-(IV), B-(II), C-(III), D-(I)
  3. C
    A-(II), B-(I), C-(IV), D-(III)
  4. D
    A-(II), B-(IV), C-(I), D-(III)
View Answer & Solution

Correct answer · Option D

A-(II), B-(IV), C-(I), D-(III)

Explanation

From Table 5.3(a) & 5.3(b): \( \text{C}-\text{C} = 347\text{ kJ mol}^{-1} \), \( \text{C}=\text{C} = 611\text{ kJ mol}^{-1} \), \( \text{C}\equiv\text{C} = 837\text{ kJ mol}^{-1} \), and \( \text{C}\equiv\text{O} = 1070\text{ kJ mol}^{-1} \). Thus, A-II, B-IV, C-I, D-III.
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat