OnlineCBT
Physics · WORK, ENERGY AND POWER
हिन्दीMatch List-I with List-II: List-I (Collision / Physical Parameter) List-II (Value / Formula) A Relative velocity of separation in 1D elastic collision (\( v_{2f} - v_{1f} \)) I \( 3.6 \times 10^6\text{ J} \) B One kilowatt hour (\( 1\text{ kWh} \)) II \( \frac{1}{2}\frac{m_1 m_2}{m_1+m_2}v_{1i}^2 \) C Loss of kinetic energy in completely inelastic 1D collision III \( 746\text{ W} \) D One horse-power (\( 1\text{ hp} \)) IV \( v_{1i} \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Collision / Physical Parameter) | List-II (Value / Formula) | ||
|---|---|---|---|
| A | Relative velocity of separation in 1D elastic collision (\( v_{2f} - v_{1f} \)) | I | \( 3.6 \times 10^6\text{ J} \) |
| B | One kilowatt hour (\( 1\text{ kWh} \)) | II | \( \frac{1}{2}\frac{m_1 m_2}{m_1+m_2}v_{1i}^2 \) |
| C | Loss of kinetic energy in completely inelastic 1D collision | III | \( 746\text{ W} \) |
| D | One horse-power (\( 1\text{ hp} \)) | IV | \( v_{1i} \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option A
A-(IV), B-(I), C-(II), D-(III)
Explanation
In 1D elastic collision with target at rest, \( v_{2f} - v_{1f} = v_{1i} \) (A-IV). \( 1\text{ kWh} = 3.6 \times 10^6\text{ J} \) (B-I). Completely inelastic loss is \( \frac{1}{2}\frac{m_1 m_2}{m_1+m_2}v_{1i}^2 \) (C-II). \( 1\text{ hp} = 746\text{ W} \) (D-III). Thus, option 1 is correct.
