Chemistry · REDOX REACTIONS
हिन्दीMatch List-I with List-II: List-I (Compound) List-II (Oxidation State of Underlined Element) A \( \underline{\text{O}}\text{F}_2 \) I +3 B \( \text{K}\underline{\text{O}}_2 \) II +2 C \( \text{Ca}\underline{\text{H}}_2 \) III \( -\frac{1}{2} \) D \( \underline{\text{Fe}}_2\text{O}_3 \) IV -1 Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I (Compound) | List-II (Oxidation State of Underlined Element) | ||
|---|---|---|---|
| A | \( \underline{\text{O}}\text{F}_2 \) | I | +3 |
| B | \( \text{K}\underline{\text{O}}_2 \) | II | +2 |
| C | \( \text{Ca}\underline{\text{H}}_2 \) | III | \( -\frac{1}{2} \) |
| D | \( \underline{\text{Fe}}_2\text{O}_3 \) | IV | -1 |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option B
A-(II), B-(III), C-(IV), D-(I)
Explanation
In \( \text{OF}_2 \), O is +2; in \( \text{KO}_2 \), O is -1/2; in \( \text{CaH}_2 \), H is -1; in \( \text{Fe}_2\text{O}_3 \), Fe is +3.