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Chemistry · REDOX REACTIONS

हिन्दी

Match List-I with List-II: List-I (Compound) List-II (Oxidation State of Underlined Element) A \( \underline{\text{O}}\text{F}_2 \) I +3 B \( \text{K}\underline{\text{O}}_2 \) II +2 C \( \text{Ca}\underline{\text{H}}_2 \) III \( -\frac{1}{2} \) D \( \underline{\text{Fe}}_2\text{O}_3 \) IV -1 Choose the correct answer from the options given below:

Match List-I with List-II:

List-I (Compound) List-II (Oxidation State of Underlined Element)
A \( \underline{\text{O}}\text{F}_2 \) I +3
B \( \text{K}\underline{\text{O}}_2 \) II +2
C \( \text{Ca}\underline{\text{H}}_2 \) III \( -\frac{1}{2} \)
D \( \underline{\text{Fe}}_2\text{O}_3 \) IV -1

Choose the correct answer from the options given below:

  1. A
    A-(II), B-(IV), C-(III), D-(I)
  2. B
    A-(II), B-(III), C-(IV), D-(I)
  3. C
    A-(III), B-(II), C-(IV), D-(I)
  4. D
    A-(I), B-(III), C-(IV), D-(II)
View Answer & Solution

Correct answer · Option B

A-(II), B-(III), C-(IV), D-(I)

Explanation

In \( \text{OF}_2 \), O is +2; in \( \text{KO}_2 \), O is -1/2; in \( \text{CaH}_2 \), H is -1; in \( \text{Fe}_2\text{O}_3 \), Fe is +3.
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