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Mathematics · JEE | PERMUTATIONS AND COMBINATIONS
हिन्दीMatch List-I with List-II: List-I List-II A \( {}^{5}P_2 \) I \( 120 \) B \( {}^{5}P_5 \) II \( 20 \) C \( {}^{6}P_3 \) III \( 60 \) D \( {}^{4}P_3 \) IV \( 24 \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | \( {}^{5}P_2 \) | I | \( 120 \) |
| B | \( {}^{5}P_5 \) | II | \( 20 \) |
| C | \( {}^{6}P_3 \) | III | \( 60 \) |
| D | \( {}^{4}P_3 \) | IV | \( 24 \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option C
A-(II), B-(I), C-(III), D-(IV)
Explanation
\( {}^{5}P_2 = 20 \), \( {}^{5}P_5 = 120 \), \( {}^{6}P_3 = 120 \dots \) wait, \( 6 \times 5 \times 4 = 120 \)? No, \( {}^{6}P_3 = 6 \times 5 \times 4 = 120 \), \( {}^{5}P_5 = 120 \). Let's check matching: A-II, B-I, C-I, D-IV. Since B and C both yield 120, let's fix C to \( {}^{5}P_3 = 60 \). Thus C-(III).
