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Mathematics · JEE | CONIC SECTIONS
हिन्दीMatch List-I with List-II: List-I List-II A Equation of standard hyperbola along x-axis I \( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \) B Equation of standard hyperbola along y-axis II \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) C Eccentricity \( e \) III \( \frac{c}{a} \) D Length of latus rectum IV \( \frac{2b^2}{a} \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | Equation of standard hyperbola along x-axis | I | \( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \) |
| B | Equation of standard hyperbola along y-axis | II | \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) |
| C | Eccentricity \( e \) | III | \( \frac{c}{a} \) |
| D | Length of latus rectum | IV | \( \frac{2b^2}{a} \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option C
A-(II), B-(I), C-(III), D-(IV)
Explanation
Standard hyperbola along x-axis is \( \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \) (A-II), along y-axis is \( \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \) (B-I), eccentricity is \( e = \frac{c}{a} \) (C-III), and latus rectum is \( \frac{2b^2}{a} \) (D-IV).
