Mathematics · JEE | APPLICATION OF DERIVATIVES
हिन्दीMatch List-I with List-II: List-I List-II A \( f(x) = \cos x \) in \( (0, \pi) \) I Strictly increasing B \( f(x) = x^3 - 3x^2 + 4x \) on \( \mathbb{R} \) II Strictly decreasing C \( f(x) = x^2 - 4x + 6 \) in \( (-\infty, 2) \) III Neither increasing nor decreasing D \( f(x) = \cos x \) in \( (0, 2\pi) \) IV Strictly decreasing in \( (-\infty, 2) \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | \( f(x) = \cos x \) in \( (0, \pi) \) | I | Strictly increasing |
| B | \( f(x) = x^3 - 3x^2 + 4x \) on \( \mathbb{R} \) | II | Strictly decreasing |
| C | \( f(x) = x^2 - 4x + 6 \) in \( (-\infty, 2) \) | III | Neither increasing nor decreasing |
| D | \( f(x) = \cos x \) in \( (0, 2\pi) \) | IV | Strictly decreasing in \( (-\infty, 2) \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option B
A-(II), B-(I), C-(IV), D-(III)
Explanation
A: \( f' = -\sin x < 0 \) in \( (0, \pi) \) (II). B: \( f' > 0 \) on \( \mathbb{R} \) (I). C: \( f' = 2x - 4 < 0 \) for \( x < 2 \) (IV). D: \( \cos x \) increases and decreases in \( (0, 2\pi) \) (III).