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Chemistry · Some Basic Concepts of Chemistry

हिन्दी

Match List-I with List-II: List-I List-II A Mass per cent I \( \frac{\text{Moles of solute}}{\text{Volume of solution in L}} \) B Molarity II \( \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100 \) C Molality III \( \frac{n_A}{n_A + n_B} \) D Mole fraction IV \( \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}} \) Choose the correct answer from the options given below:

Match List-I with List-II:

List-I List-II
A Mass per cent I \( \frac{\text{Moles of solute}}{\text{Volume of solution in L}} \)
B Molarity II \( \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100 \)
C Molality III \( \frac{n_A}{n_A + n_B} \)
D Mole fraction IV \( \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}} \)

Choose the correct answer from the options given below:

  1. A
    A-(I), B-(II), C-(III), D-(IV)
  2. B
    A-(II), B-(I), C-(IV), D-(III)
  3. C
    A-(IV), B-(III), C-(II), D-(I)
  4. D
    A-(II), B-(III), C-(I), D-(IV)
View Answer & Solution

Correct answer · Option B

A-(II), B-(I), C-(IV), D-(III)

Explanation

Correct matching is: - Mass per cent (A) = \(\frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100\) (II) - Molarity (B) = \(\frac{\text{Moles of solute}}{\text{Volume of solution in L}}\) (I) - Molality (C) = \(\frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}\) (IV) - Mole fraction (D) = \(\frac{n_A}{n_A + n_B}\) (III) Therefore, A-(II), B-(I), C-(IV), D-(III).
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