Physics · JEE | KINETIC THEORY
हिन्दीMatch List-I with List-II: List-I List-II A Mean free path I Order of \( 10^{-10} \text{ m} \) B Atomic size II Order of thousands of angstroms C Boltzmann constant (\( k_B \)) III \( 1.38 \times 10^{-23} \text{ J K}^{-1} \) D Avogadro number (\( N_A \)) IV \( 6.02 \times 10^{23} \text{ mol}^{-1} \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | Mean free path | I | Order of \( 10^{-10} \text{ m} \) |
| B | Atomic size | II | Order of thousands of angstroms |
| C | Boltzmann constant (\( k_B \)) | III | \( 1.38 \times 10^{-23} \text{ J K}^{-1} \) |
| D | Avogadro number (\( N_A \)) | IV | \( 6.02 \times 10^{23} \text{ mol}^{-1} \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option D
A-(II), B-(I), C-(III), D-(IV)
Explanation
Mean free path in gases is of the order of thousands of angstroms, atomic size is about \( 10^{-10} \text{ m} \), \( k_B = 1.38 \times 10^{-23} \text{ J K}^{-1} \), and \( N_A = 6.02 \times 10^{23} \text{ mol}^{-1} \).