Mathematics · JEE | PERMUTATIONS AND COMBINATIONS
हिन्दीMatch List-I with List-II: List-I List-II A \( {^n\text{P}_r} \) I \( \frac{n!}{r!(n-r)!} \) B \( {^n\text{C}_r} \) II \( \frac{n!}{(n-r)!} \) C \( {^n\text{C}_0} \) III \( n! \) D \( {^n\text{P}_n} \) IV \( 1 \) Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II | ||
|---|---|---|---|
| A | \( {^n\text{P}_r} \) | I | \( \frac{n!}{r!(n-r)!} \) |
| B | \( {^n\text{C}_r} \) | II | \( \frac{n!}{(n-r)!} \) |
| C | \( {^n\text{C}_0} \) | III | \( n! \) |
| D | \( {^n\text{P}_n} \) | IV | \( 1 \) |
Choose the correct answer from the options given below:
View Answer & Solution
Correct answer · Option A
A-(II), B-(I), C-(IV), D-(III)
Explanation
Matching formulas: \( {^n\text{P}_r} = \frac{n!}{(n-r)!} \), \( {^n\text{C}_r} = \frac{n!}{r!(n-r)!} \), \( {^n\text{C}_0} = 1 \), and \( {^n\text{P}_n} = n! \).