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Physics · MOTION IN A PLANE

हिन्दी

Match List-I with List-II: List-I List-II A Time of flight \( T_f \) I \( \frac{2v_o\sin\theta_o}{g} \) B Maximum height \( h_m \) II \( \frac{v_o^2\sin^2\theta_o}{2g} \) C Horizontal range \( R \) III \( \frac{v_o^2\sin 2\theta_o}{g} \) D Angle of projection for maximum range IV \( 45^\circ \) Choose the correct answer from the options given below:

Match List-I with List-II:

List-I List-II
A Time of flight \( T_f \) I \( \frac{2v_o\sin\theta_o}{g} \)
B Maximum height \( h_m \) II \( \frac{v_o^2\sin^2\theta_o}{2g} \)
C Horizontal range \( R \) III \( \frac{v_o^2\sin 2\theta_o}{g} \)
D Angle of projection for maximum range IV \( 45^\circ \)

Choose the correct answer from the options given below:

  1. A
    A-(II), B-(I), C-(III), D-(IV)
  2. B
    A-(I), B-(III), C-(II), D-(IV)
  3. C
    A-(III), B-(II), C-(I), D-(IV)
  4. D
    A-(I), B-(II), C-(III), D-(IV)
View Answer & Solution

Correct answer · Option D

A-(I), B-(II), C-(III), D-(IV)

Explanation

The standard projectile formulas are \( T_f = \frac{2v_o\sin\theta_o}{g} \), \( h_m = \frac{v_o^2\sin^2\theta_o}{2g} \), \( R = \frac{v_o^2\sin 2\theta_o}{g} \), and maximum range occurs at \( \theta_o = 45^\circ \).
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