OnlineCBT Logo OnlineCBT

Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE

हिन्दी

Match List-I with List-II: List-I (Molecule) List-II (Dipole moment in Debye) A \( \text{HF} \) I \( 0.23 \) B \( \text{H}_2\text{S} \) II \( 1.78 \) C \( \text{NH}_3 \) III \( 0.95 \) D \( \text{NF}_3 \) IV \( 1.47 \) Choose the correct answer from the options given below:

Match List-I with List-II:

List-I (Molecule) List-II (Dipole moment in Debye)
A \( \text{HF} \) I \( 0.23 \)
B \( \text{H}_2\text{S} \) II \( 1.78 \)
C \( \text{NH}_3 \) III \( 0.95 \)
D \( \text{NF}_3 \) IV \( 1.47 \)

Choose the correct answer from the options given below:

  1. A
    A-(II), B-(IV), C-(III), D-(I)
  2. B
    A-(II), B-(III), C-(IV), D-(I)
  3. C
    A-(III), B-(II), C-(IV), D-(I)
  4. D
    A-(I), B-(III), C-(IV), D-(II)
View Answer & Solution

Correct answer · Option B

A-(II), B-(III), C-(IV), D-(I)

Explanation

From Table 4.5: HF = 1.78 D, H2S = 0.95 D, NH3 = 1.47 D, NF3 = 0.23 D.
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat