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Physics · JEE | Electric Charges and Fields

हिन्दी

Match List-I with List-II: \n List-I List-II A Gold-leaf electroscope I Measures force between small charged spheres B Torsion balance II Detects charge on a body C Electric dipole moment III Product of charge and separation D Permittivity of free space (\( \varepsilon_0 \)) IV \( 8.854 \times 10^{-12}\text{ C}^2\text{N}^{-1}\text{m}^{-2} \) \n Choose the correct answer from the options given below:

Match List-I with List-II:

\n
List-I List-II
A Gold-leaf electroscope I Measures force between small charged spheres
B Torsion balance II Detects charge on a body
C Electric dipole moment III Product of charge and separation
D Permittivity of free space (\( \varepsilon_0 \)) IV \( 8.854 \times 10^{-12}\text{ C}^2\text{N}^{-1}\text{m}^{-2} \)
\n

Choose the correct answer from the options given below:

  1. A
    A-(I), B-(II), C-(III), D-(IV)
  2. B
    A-(II), B-(I), C-(III), D-(IV)
  3. C
    A-(III), B-(II), C-(I), D-(IV)
  4. D
    A-(II), B-(III), C-(IV), D-(I)
View Answer & Solution

Correct answer · Option B

A-(II), B-(I), C-(III), D-(IV)

Explanation

Gold-leaf electroscope detects charge, torsion balance measures force, electric dipole moment is \( q \times 2a \), and \( \varepsilon_0 = 8.854 \times 10^{-12}\text{ C}^2\text{N}^{-1}\text{m}^{-2} \).
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