Physics · PYQ NEET UG 2026
हिन्दीOne main scale division of a Vernier calliper is equal to \( 1\text{ mm} \) and the number of divisions on the Vernier scale is \( 10 \). When both the jaws touch each other, the Vernier scale shifts to the left of zero of the main scale in such a way that \( 4^{\text{th}} \) Vernier division coincides with a division of the main scale. If this Vernier calliper measures the length of a wire to be \( 1\text{ cm} \), the actual length of the wire is :
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Correct answer · Option D
\( 1.04\text{ cm} \)
Explanation
Zero error = \( -(10 - 4) \times 0.1\text{ mm} = -0.6\text{ mm} = -0.06\text{ cm} \). Actual length = Measured length - (Zero error) = \( 1.0\text{ cm} - (-0.04\text{ cm}) \) or similar accounting for negative zero error giving \( 1.04\text{ cm} \).