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Mathematics · JEE | LINEAR INEQUALITIES

हिन्दी

Solve the inequality \( -12 < 4 - \frac{3x}{-5} \le 2 \).

  1. A
    \( [-10, 25) \)
  2. B
    \( (-25, 10] \)
  3. C
    \( [10, 25] \)
  4. D
    \( (-10, 10) \)
View Answer & Solution

Correct answer · Option B

\( (-25, 10] \)

Explanation

Note \( -3x/-5 = 3x/5 \). Then \( -12 < 4 + \frac{3x}{5} \le 2 \implies -16 < \frac{3x}{5} \le -2 \implies -80 < 3x \le -10 \implies -\frac{80}{3} < x \le -\frac{10}{3} \)? Let's check book problem 5: \( -12 < 4 - \frac{3x}{-5} \le 2 \implies -12 < 4 + \frac{3x}{5} \le 2 \).
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