असमानता \( -12 < 4 - \frac{3x}{-5} \le 2 \) को हल करें।

Note \( -3x/-5 = 3x/5 \). Then \( -12 < 4 + \frac{3x}{5} \le 2 \implies -16 < \frac{3x}{5} \le -2 \implies -80 < 3x \le -10 \implies -\frac{80}{3} < x \le -\frac{10}{3} \)? Let's check book problem 5: \( -12 < 4 - \frac{3x}{-5} \le 2 \implies -12 < 4 + \frac{3x}{5} \le 2 \).