Solve the inequality \( 6 \le -3(2x - 4) < 12 \).

Divide by -3 and reverse signs: \( -4 < 2x - 4 \le -2 \). Add 4: \( 0 < 2x \le 2 \). Divide by 2: \( 0 < x \le 1 \)? Wait, let's re-solve: \( 6 \le -6x + 12 < 12 \implies -6 \le -6x < 0 \implies 0 < x \le 1 \). Interval is \( (0, 1] \).