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Physics · JEE | MECHANICAL PROPERTIES OF FLUIDS

हिन्दी

Stokes' law gives the viscous drag force \( F \) acting on a spherical body of radius \( a \) moving with velocity \( v \) through a fluid of viscosity \( \eta \). The correct expression is:

  1. A
    \( F = 4\pi\eta a v \)
  2. B
    \( F = \frac{4}{3}\pi\eta a v \)
  3. C
    \( F = 6\pi\eta a v \)
  4. D
    \( F = 2\pi\eta a v^2 \)
View Answer & Solution

Correct answer · Option C

\( F = 6\pi\eta a v \)

Explanation

Stokes' law formula is \( F = 6\pi\eta a v \).
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