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Chemistry · PYQ NEET UG 2016(2)

हिन्दी

The CORRECT geometry and hybridization for \( \text{XeF}_4 \) are ______ respectively.

  1. A
    square planar, \( \text{sp}^3\text{d}^2 \)
  2. B
    octahedral, \( \text{sp}^3\text{d}^2 \)
  3. C
    trigonal bipyramidal, \( \text{sp}^3\text{d} \)
  4. D
    planar triangle, \( \text{sp}^3\text{d}^3 \)
View Answer & Solution

Correct answer · Option A

square planar, \( \text{sp}^3\text{d}^2 \)

Explanation

Xe in \( \text{XeF}_4 \) has 6 electron pairs (4 bond pairs + 2 lone pairs), leading to \( \text{sp}^3\text{d}^2 \) hybridization and square planar geometry.
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