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Physics · JEE | UNITS AND MEASUREMENT
हिन्दीThe dimensional formula of the universal gravitational constant \( G \) in terms of fundamental dimensions \( [M], [L], [T] \) is given by:
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Correct answer · Option B
\( [M^{-1} L^3 T^{-2}] \)
Explanation
From Newton's law of gravitation, \( F = \frac{G m_1 m_2}{r^2} \implies G = \frac{F r^2}{m_1 m_2} \). Substituting dimensions: \( \frac{[MLT^{-2}][L^2]}{[M^2]} = [M^{-1}L^3T^{-2}] \).
