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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीThe dipole moment of \( \text{HF} \) is \( 1.78\text{ D} \) with bond length \( 92\text{ pm} \), while for \( \text{HI} \) it is \( 0.38\text{ D} \) with bond length \( 160\text{ pm} \). What is the ratio of the partial charge on the halogen atom in \( \text{HF} \) to that in \( \text{HI} \) (i.e., \( q_F / q_I \))?
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Correct answer · Option D
\( 8.15 \)
Explanation
\( q = \frac{\mu}{d} \). Therefore, \( \frac{q_F}{q_I} = \frac{\mu_{\text{HF}} / d_{\text{HF}}}{\mu_{\text{HI}} / d_{\text{HI}}} = \frac{1.78 / 92}{0.38 / 160} = \frac{0.01935}{0.002375} \approx 8.15 \).
