Physics · JEE | Electric Charges and Fields

The electric flux \( \Delta\phi \) through a small area element \( \Delta\mathbf{S} \) in a uniform electric field \( \mathbf{E} \) is given by \( \Delta\phi = \mathbf{E}\cdot\Delta\mathbf{S} = E\Delta S\cos\theta \). If the angle \( \theta \) between \( \mathbf{E} \) and the outward normal vector of the area element is \( 60^\circ \), the ratio of the actual electric flux to the maximum possible flux through this area element is:

1. A
   1.0
2. B
   0.5
3. C
   0.866
4. D
   0.25