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Physics · Electrostatic Potential

English

निर्वात में \( r_{12} \) दूरी से अलग किए गए दो बिंदु आवेशों \( q_1 \) और \( q_2 \) के निकाय की स्थिरवैद्युत स्थितिज ऊर्जा \( U \) को इस प्रकार व्यक्त किया जाता है:

  1. A
    \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \)
  2. B
    \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}^2} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}^2} \)
  3. C
    \( U = \frac{1}{4\pi\varepsilon_0} \frac{(q_1 + q_2)}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{(q_1 + q_2)}{r_{12}} \)
  4. D
    \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1^2 q_2^2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1^2 q_2^2}{r_{12}} \)
उत्तर और समाधान देखें

सही उत्तर · विकल्प A

\( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \) / \( U = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r_{12}} \)

व्याख्या

The potential energy of a two-charge system is given by the product of charges divided by \( 4\pi\varepsilon_0 \) times their separation distance \( r_{12} \).
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