OnlineCBT Logo OnlineCBT

Chemistry · PYQ NEET UG 2017

हिन्दी

The equilibrium constants of the following are: \( \text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3 \; ; \text{K}_1 \) \( \text{N}_2 + \text{O}_2 \rightleftharpoons 2\text{NO} \; ; \text{K}_2 \) \( \text{H}_2 + \frac{1}{2}\text{O}_2 \longrightarrow \text{H}_2\text{O} \; ; \text{K}_3 \)\nThe equilibrium constant (K) of the reaction: \( 2\text{NH}_3 + \frac{5}{2}\text{O}_2 \stackrel{\text{K}}{\rightleftharpoons} 2\text{NO} + 3\text{H}_2\text{O} \), will be

  1. A
    \( \frac{\text{K}_1\text{K}_3^3}{\text{K}_2} \)
  2. B
    \( \frac{\text{K}_2\text{K}_3^3}{\text{K}_1} \)
  3. C
    \( \frac{\text{K}_2\text{K}_3}{\text{K}_1} \)
  4. D
    \( \frac{\text{K}_2^3\text{K}_3}{\text{K}_1} \)
View Answer & Solution

Correct answer · Option B

\( \frac{\text{K}_2\text{K}_3^3}{\text{K}_1} \)

Explanation

Combining equations: \( \text{K} = \frac{\text{K}_2 \times \text{K}_3^3}{\text{K}_1} \).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat