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Chemistry · PYQ NEET UG 2021

हिन्दी

The following solutions were prepared by dissolving 10 g of glucose \( (\text{C}_6\text{H}_{12}\text{O}_6) \) in 250 mL of water \( (\text{P}_1) \), 10 g of urea \( (\text{CH}_4\text{N}_2\text{O}) \) in 250 mL of water \( (\text{P}_2) \) and 10 g of sucrose \( (\text{C}_{12}\text{H}_{22}\text{O}_{11}) \) in 250 ml of water \( (\text{P}_3) \). The right option for the decreasing order of osmotic pressure of these solutions is _______.

  1. A
    \( \text{P}_1 > \text{P}_2 > \text{P}_3 \)
  2. B
    \( \text{P}_2 > \text{P}_3 > \text{P}_1 \)
  3. C
    \( \text{P}_3 > \text{P}_1 > \text{P}_2 \)
  4. D
    \( \text{P}_2 > \text{P}_1 > \text{P}_3 \)
View Answer & Solution

Correct answer · Option D

\( \text{P}_2 > \text{P}_1 > \text{P}_3 \)

Explanation

Osmotic pressure \( \pi \propto \text{molarity} \propto \frac{1}{\text{Molar mass}} \). Molar masses: Urea (60) < Glucose (180) < Sucrose (342). Thus, \( \text{P}_2 > \text{P}_1 > \text{P}_3 \).
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