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Physics · GRAVITATION
हिन्दीThe gravitational force between two point masses \( m_1 \) and \( m_2 \) separated by distance \( r \) is \( F \). If the mass \( m_1 \) is increased by \( 100\% \), mass \( m_2 \) is decreased by \( 50\% \), and the distance between them is halved, the new gravitational force will be:
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Correct answer · Option C
\( 4F \)
Explanation
New masses are \( m_1' = 2m_1 \), \( m_2' = 0.5m_2 \), and new distance is \( r' = r/2 \). Thus, \( F' = \frac{G(2m_1)(0.5m_2)}{(r/2)^2} = \frac{1}{(1/4)} F = 4F \).
