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Physics · PYQ NEET UG 2021
हिन्दीThe half-life of a radioactive nuclide is \( 100\text{ hours} \). The fraction of original activity that will remain after \( 150\text{ hours} \) would be:
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Correct answer · Option A
\( \frac{1}{2\sqrt{2}} \)
Explanation
Activity \( A = A_0 (\frac{1}{2})^{t/T_{1/2}} = A_0 (\frac{1}{2})^{150/100} = A_0 (\frac{1}{2})^{3/2} = \frac{A_0}{2\sqrt{2}} \). Thus, fraction remaining is \( \frac{1}{2\sqrt{2}} \).
