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Physics · JEE | Alternating Current

हिन्दी

The instantaneous power \( p_L \) supplied to an inductor carrying current \( i = -i_m \cos(\omega t) \) with voltage \( v = v_m \sin(\omega t) \) is given by:

  1. A
    \( i_m v_m \sin^2(\omega t) \)
  2. B
    \( \frac{i_m v_m}{2} \cos(2\omega t) \)
  3. C
    \( -\frac{i_m v_m}{2} \sin(2\omega t) \)
  4. D
    \( i_m v_m \cos^2(\omega t) \)
View Answer & Solution

Correct answer · Option C

\( -\frac{i_m v_m}{2} \sin(2\omega t) \)

Explanation

Using trigonometric identities, \( p_L = -i_m v_m \cos(\omega t)\sin(\omega t) = -\frac{i_m v_m}{2}\sin(2\omega t) \).
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