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Physics · JEE | Electrostatic Potential and Capacitance

हिन्दी

The magnitude of the electric field \( |E| \) in terms of potential change \( \delta V \) and perpendicular distance \( \delta l \) across closely spaced equipotential surfaces is given by:

  1. A
    \( |E| = -\frac{\delta V}{\delta l} \)
  2. B
    \( |E| = \frac{\delta l}{\delta V} \)
  3. C
    \( |E| = \delta V \cdot \delta l \)
  4. D
    \( |E| = \left|\frac{\delta V}{\delta l}\right| \)
View Answer & Solution

Correct answer · Option D

\( |E| = \left|\frac{\delta V}{\delta l}\right| \)

Explanation

The magnitude of the electric field is given by the negative gradient of potential, specifically \( |E| = |-\frac{\delta V}{\delta l}| = \frac{|\delta V|}{\delta l} \).
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