Physics · JEE | Electrostatic Potential and Capacitance
हिन्दीThe magnitude of the electric field \( |E| \) in terms of potential change \( \delta V \) and perpendicular distance \( \delta l \) across closely spaced equipotential surfaces is given by:
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Correct answer · Option D
\( |E| = \left|\frac{\delta V}{\delta l}\right| \)
Explanation
The magnitude of the electric field is given by the negative gradient of potential, specifically \( |E| = |-\frac{\delta V}{\delta l}| = \frac{|\delta V|}{\delta l} \).